3.20.53 \(\int \frac {(3+5 x)^2}{(1-2 x)^{3/2} (2+3 x)^4} \, dx\)

Optimal. Leaf size=108 \[ -\frac {905 \sqrt {1-2 x}}{2058 (3 x+2)}-\frac {905 \sqrt {1-2 x}}{882 (3 x+2)^2}-\frac {467 \sqrt {1-2 x}}{126 (3 x+2)^3}+\frac {121}{14 \sqrt {1-2 x} (3 x+2)^3}-\frac {905 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{1029 \sqrt {21}} \]

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Rubi [A]  time = 0.03, antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {89, 78, 51, 63, 206} \begin {gather*} -\frac {905 \sqrt {1-2 x}}{2058 (3 x+2)}-\frac {905 \sqrt {1-2 x}}{882 (3 x+2)^2}-\frac {467 \sqrt {1-2 x}}{126 (3 x+2)^3}+\frac {121}{14 \sqrt {1-2 x} (3 x+2)^3}-\frac {905 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{1029 \sqrt {21}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(3 + 5*x)^2/((1 - 2*x)^(3/2)*(2 + 3*x)^4),x]

[Out]

121/(14*Sqrt[1 - 2*x]*(2 + 3*x)^3) - (467*Sqrt[1 - 2*x])/(126*(2 + 3*x)^3) - (905*Sqrt[1 - 2*x])/(882*(2 + 3*x
)^2) - (905*Sqrt[1 - 2*x])/(2058*(2 + 3*x)) - (905*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(1029*Sqrt[21])

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 89

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c - a*
d)^2*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d^2*(d*e - c*f)*(n + 1)), x] - Dist[1/(d^2*(d*e - c*f)*(n + 1)), In
t[(c + d*x)^(n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*(p + 1)) - 2*a*b*d*(d*e*
(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ
[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] ||  !SumSimplerQ[p, 1])))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(3+5 x)^2}{(1-2 x)^{3/2} (2+3 x)^4} \, dx &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)^3}-\frac {1}{14} \int \frac {-973+175 x}{\sqrt {1-2 x} (2+3 x)^4} \, dx\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)^3}-\frac {467 \sqrt {1-2 x}}{126 (2+3 x)^3}+\frac {905}{63} \int \frac {1}{\sqrt {1-2 x} (2+3 x)^3} \, dx\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)^3}-\frac {467 \sqrt {1-2 x}}{126 (2+3 x)^3}-\frac {905 \sqrt {1-2 x}}{882 (2+3 x)^2}+\frac {905}{294} \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2} \, dx\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)^3}-\frac {467 \sqrt {1-2 x}}{126 (2+3 x)^3}-\frac {905 \sqrt {1-2 x}}{882 (2+3 x)^2}-\frac {905 \sqrt {1-2 x}}{2058 (2+3 x)}+\frac {905 \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx}{2058}\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)^3}-\frac {467 \sqrt {1-2 x}}{126 (2+3 x)^3}-\frac {905 \sqrt {1-2 x}}{882 (2+3 x)^2}-\frac {905 \sqrt {1-2 x}}{2058 (2+3 x)}-\frac {905 \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )}{2058}\\ &=\frac {121}{14 \sqrt {1-2 x} (2+3 x)^3}-\frac {467 \sqrt {1-2 x}}{126 (2+3 x)^3}-\frac {905 \sqrt {1-2 x}}{882 (2+3 x)^2}-\frac {905 \sqrt {1-2 x}}{2058 (2+3 x)}-\frac {905 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{1029 \sqrt {21}}\\ \end {align*}

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Mathematica [C]  time = 0.02, size = 59, normalized size = 0.55 \begin {gather*} \frac {7240 (2 x-1) (3 x+2)^3 \, _2F_1\left (\frac {1}{2},3;\frac {3}{2};\frac {3}{7}-\frac {6 x}{7}\right )+343 (467 x+311)}{21609 \sqrt {1-2 x} (3 x+2)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(3 + 5*x)^2/((1 - 2*x)^(3/2)*(2 + 3*x)^4),x]

[Out]

(343*(311 + 467*x) + 7240*(-1 + 2*x)*(2 + 3*x)^3*Hypergeometric2F1[1/2, 3, 3/2, 3/7 - (6*x)/7])/(21609*Sqrt[1
- 2*x]*(2 + 3*x)^3)

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IntegrateAlgebraic [A]  time = 0.24, size = 79, normalized size = 0.73 \begin {gather*} \frac {8145 (1-2 x)^3-50680 (1-2 x)^2+104419 (1-2 x)-71148}{1029 (3 (1-2 x)-7)^3 \sqrt {1-2 x}}-\frac {905 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{1029 \sqrt {21}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(3 + 5*x)^2/((1 - 2*x)^(3/2)*(2 + 3*x)^4),x]

[Out]

(-71148 + 104419*(1 - 2*x) - 50680*(1 - 2*x)^2 + 8145*(1 - 2*x)^3)/(1029*(-7 + 3*(1 - 2*x))^3*Sqrt[1 - 2*x]) -
(905*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(1029*Sqrt[21])

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fricas [A]  time = 1.17, size = 99, normalized size = 0.92 \begin {gather*} \frac {905 \, \sqrt {21} {\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )} \log \left (\frac {3 \, x + \sqrt {21} \sqrt {-2 \, x + 1} - 5}{3 \, x + 2}\right ) - 21 \, {\left (16290 \, x^{3} + 26245 \, x^{2} + 13747 \, x + 2316\right )} \sqrt {-2 \, x + 1}}{43218 \, {\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(3/2)/(2+3*x)^4,x, algorithm="fricas")

[Out]

1/43218*(905*sqrt(21)*(54*x^4 + 81*x^3 + 18*x^2 - 20*x - 8)*log((3*x + sqrt(21)*sqrt(-2*x + 1) - 5)/(3*x + 2))
- 21*(16290*x^3 + 26245*x^2 + 13747*x + 2316)*sqrt(-2*x + 1))/(54*x^4 + 81*x^3 + 18*x^2 - 20*x - 8)

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giac [A]  time = 1.23, size = 93, normalized size = 0.86 \begin {gather*} \frac {905}{43218} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {484}{2401 \, \sqrt {-2 \, x + 1}} - \frac {17811 \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} - 80332 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 90601 \, \sqrt {-2 \, x + 1}}{57624 \, {\left (3 \, x + 2\right )}^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(3/2)/(2+3*x)^4,x, algorithm="giac")

[Out]

905/43218*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 484/2401/sqrt(
-2*x + 1) - 1/57624*(17811*(2*x - 1)^2*sqrt(-2*x + 1) - 80332*(-2*x + 1)^(3/2) + 90601*sqrt(-2*x + 1))/(3*x +
2)^3

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maple [A]  time = 0.02, size = 66, normalized size = 0.61 \begin {gather*} -\frac {905 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{21609}+\frac {484}{2401 \sqrt {-2 x +1}}+\frac {\frac {5937 \left (-2 x +1\right )^{\frac {5}{2}}}{2401}-\frac {11476 \left (-2 x +1\right )^{\frac {3}{2}}}{1029}+\frac {1849 \sqrt {-2 x +1}}{147}}{\left (-6 x -4\right )^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x+3)^2/(-2*x+1)^(3/2)/(3*x+2)^4,x)

[Out]

484/2401/(-2*x+1)^(1/2)+108/2401*(1979/36*(-2*x+1)^(5/2)-20083/81*(-2*x+1)^(3/2)+90601/324*(-2*x+1)^(1/2))/(-6
*x-4)^3-905/21609*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.30, size = 101, normalized size = 0.94 \begin {gather*} \frac {905}{43218} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) - \frac {8145 \, {\left (2 \, x - 1\right )}^{3} + 50680 \, {\left (2 \, x - 1\right )}^{2} + 208838 \, x - 33271}{1029 \, {\left (27 \, {\left (-2 \, x + 1\right )}^{\frac {7}{2}} - 189 \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} + 441 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 343 \, \sqrt {-2 \, x + 1}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^2/(1-2*x)^(3/2)/(2+3*x)^4,x, algorithm="maxima")

[Out]

905/43218*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 1/1029*(8145*(2*x - 1)^
3 + 50680*(2*x - 1)^2 + 208838*x - 33271)/(27*(-2*x + 1)^(7/2) - 189*(-2*x + 1)^(5/2) + 441*(-2*x + 1)^(3/2) -
343*sqrt(-2*x + 1))

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mupad [B]  time = 0.07, size = 82, normalized size = 0.76 \begin {gather*} \frac {\frac {4262\,x}{567}+\frac {7240\,{\left (2\,x-1\right )}^2}{3969}+\frac {905\,{\left (2\,x-1\right )}^3}{3087}-\frac {97}{81}}{\frac {343\,\sqrt {1-2\,x}}{27}-\frac {49\,{\left (1-2\,x\right )}^{3/2}}{3}+7\,{\left (1-2\,x\right )}^{5/2}-{\left (1-2\,x\right )}^{7/2}}-\frac {905\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{21609} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x + 3)^2/((1 - 2*x)^(3/2)*(3*x + 2)^4),x)

[Out]

((4262*x)/567 + (7240*(2*x - 1)^2)/3969 + (905*(2*x - 1)^3)/3087 - 97/81)/((343*(1 - 2*x)^(1/2))/27 - (49*(1 -
2*x)^(3/2))/3 + 7*(1 - 2*x)^(5/2) - (1 - 2*x)^(7/2)) - (905*21^(1/2)*atanh((21^(1/2)*(1 - 2*x)^(1/2))/7))/216
09

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)**2/(1-2*x)**(3/2)/(2+3*x)**4,x)

[Out]

Timed out

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